Complete question : Two hikers are 33 miles apart and walking toward each other. They meet in 5 hours. Find the rate of each hiker if one hiker walks 2.2 mph faster than the other. The speed of the slow hiker is nothing mph, and the speed of the fast hiker is nothing mph.
Answer:
2.2 mph ; 4.4 mph
Step-by-step explanation:
Given that :
Total distance apart = 33
Time taken = 5 hours
Rate of slow hiker = x
Rate of fast hiker = x + 2.2
Speed (rate) = distance / time
Distance = speed * time
Distance covered by fast hiker + distance covers by slow hiker
(x + 2.2)*5 + 5x = 33
5x + 11 + 5x = 33
10x = 33 - 11
10x = 22
x = 22 / 10
x = 2.2
Rate of slow hiker = 2.2 mph
Rate of fat hike = x + 2.2 = 2.2 + 2.2 = 4.4 moj
