Answer:
The value of x lies between 20 and 40 and value of y lies between -20 and 10
Step-by-step explanation:
We are given that
[tex]y\leq 40-x[/tex]....(1)
[tex]y\leq x-20[/tex]...(2)
First we convert inequality equation into equality equation to find the solution of the given system of inequality equation.
Therefore, we can write as
[tex]y=-x+40[/tex]...(3)
[tex]y=x-20[/tex]...(4)
Adding equation (3) and (4) we get
[tex]2y=20[/tex]
[tex]y=10[/tex]
Substitute y=10 in equation (3) we get
[tex]10=40-x[/tex]
[tex]x=40-10=30[/tex]
(30,10) is the intersect point of two equation.
Put x=0 in equation (3)
[tex]y=40[/tex]
Substitute y=0 in equation (3)
[tex]x=40[/tex]
Substitute x=0 in equation (4)
[tex]y=-20[/tex]
Substitute y=0 in equation (4)
[tex]x=20[/tex]
Substitute x=0 and y=40 and in equation (1)
[tex]40\leq 40[/tex]
Hence, the equation is true.Therefore, the shaded region below the line.
Substitute x=0 and y=-20 in equation (2)
[tex]-20\leq -20[/tex]
The equation is true. Hence, the shaded region is below the line.
Hence, the value of x lies between 20 and 40 and value of y lies between -20 and 10.
