Answer:
2.66 g of Fe, can be obtained from the reaction
Explanation:
Let's think the reaction:
2Fe₂O₃ + 6CO → 4Fe + 6CO₂
Ratio is 2:4, so If i have x moles of iron (III) oxide, I will produce the double of moles of Fe.
Mass / Molar mass = Mol
3.80 g / 159.7 g/m = 0.0237 moles
0.0237 moles . 2 = 0.0475 moles
Molar mass Fe = 55.85 g/m
Mol . Molar mass = Mass → 0.0475 m . 55.85 g/m = 2.66 grams
Explanation:
