A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis
racket and rebounds horizontally at a speed of 40 m/s.

Before hitting the Racket, the ball is going towards the racket at 25 m/s.

After Hitting the Racket the ball of going away from the racket at 40 m/s.

The ball is in contact with the racket for 50 ms.
What force does the racket exert on the ball?
A 0.018N
B 0.078N
C 18N
D 78N

I got A as the answer
Explanation:
Subtract the final velocity by the starting velocity and the divide by the time,
40-25= 15, so then divide 15 by the time ,50, to get 0.3. Now that the velocity is know u then multiple 0.3 by the mass of the tennis ball, 0.060, to get 0.018 Newton’s as the force being exerted.

Answer Link

poojatomarb76 poojatomarb76 · Answer 2 · 2022-05-06T12:01:41+02:00

The force does the racket exert on the ball will be 18 N. Force is defined as the product of mass and acceleration. Its unit is Newton.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

The mass of tennis ball is, [tex]\rm m= 0.060 \ kg[/tex]

The speed of tennis ball is,[tex]\rm u = 25m/s[/tex]

The rebound's speed is,[tex]\rm v = 40 \ m/sec[/tex]

The time period of ball is in contact,[tex]\rm t=50 \ ms =50 \times 10^{-3} \ sec[/tex]

The force on the rocket is found as;

[tex]\rm F= m [\frac{v-u}{t}] \\\\\ \rm F= 0.060[ \frac{40-25}{50 \times 10^{-3}} ]\\\\\ F= 18 \ N[/tex]

Hence, the force does the racket exert on the ball will be 18 N.

To learn more about the force, refer to the link;

https://brainly.com/question/26115859

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