Find the distance from point (0,3) to the line y=3x-9
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Answer:
The distance from a point to the line
[tex]d = \frac{9}{\sqrt{10} }[/tex]
Step-by-step explanation:
Explanation:-
Given straight line y = 3x-9 and point ( 0, 3)
Given straight line 3 x - y -9 =0
The distance from a point to the line
[tex]d = \frac{ax_{1} +by_{1} +c_{1} }{\sqrt{a^{2} +b^{2} } }[/tex]
[tex]d = |\frac{3(0) -3 -9 }{\sqrt{3^{2} +1^{2} } }|[/tex]
[tex]d = \frac{9}{\sqrt{10} }[/tex]