Answer:
Step-by-step explanation:
Function rule:
y = 10(0.95)ˣ
If a function is given as,
y = a(b)ˣ
a represents 'Initial value'
b represents the growth factor
If 0 < b < 1, function is a decay function.
If b > 1, function is a growth function.
For 2 = 10(0.95)ˣ,
Here, b = 0.95 which is in the interval of 0 < 0.95 < 1
So it's a decay function.
[tex]\frac{2}{10}=(0.95)^x[/tex]
log(0.2) = log[(0.95)ˣ]
log(0.2) = x[log(0.95)]
-0.6989 = -x(0.0223)
x = 31.44
x ≈ 31
Meaning → For 'x' = 31, value of the function is 2.
For 8 = 10(0.95)ˣ,
0.8 = (0.95)ˣ
log(0.8) = log(0.95ˣ)
log(0.8) = xlog(0.95)
x = 4.35 ≈ 4.4
Means, at x = 4.4, value of the function was 8.
