Answer:
Quotient = (3x-1)
Step-by-step explanation:
we need to find the quotient when (3x² + 8x -3) is divided by (x+3)
It means we need to divide (3x² + 8x -3) by (x+3).
We can write it as follows :
[tex]\dfrac{3x^2 + 8x -3}{(x+3)}[/tex]
Applying middle term splitting on the numerator.
[tex]\dfrac{3x^2 +9x-x-3}{(x+3)}\\\\=\dfrac{3x(x+3)-1(x+3)}{(x+3)}\\\\=\dfrac{(3x-1)(x+3)}{(x+3)}\\\\=(3x-1)[/tex]
So, the required quotient is (3x-1)
