The half-reactions for the galvanic cell with aluminum and gold electrodes is [tex]\mathbf{Al_{(s)}\to Al^{3+} _{(aq) } + 3e^- \ and \ Au^+_{(aq)} +e^- \to Au_{(s)}}[/tex]
Galvanic cells are electrochemical cells that generate electrical energy by the spontaneous activity in the oxidation-reduction (redox) reaction process.
The position of the metals if they are going to be at the cathode or at the anode relatively depends on the position with which they find themselves in the electrochemical series. The higher metal will be the anode and the lower metal in the electrochemical series will be the cathode.
Since aluminum is higher than gold on the electrochemical series, then:
- Aluminum = anode (oxidation of aluminum from solid to aqueous state)
- Gold = cathode (reduction of gold from aqueous to solid-state)
Therefore, the half-reactions for the galvanic cell with aluminum and gold electrodes is [tex]\mathbf{Al_{(s)}\to Al^{3+} _{(aq) } + 3e^- \ and \ Au^+_{(aq)} +e^- \to Au_{(s)}}[/tex]
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