Answer: [tex]56\times 10^{20}\ \text{atoms}[/tex]
Explanation:
Given
No. of moles of [tex]Na_{2}CO_{3}[/tex] is [tex]9.30\times 10^{-3}[/tex]
So, for [tex]9.30\times 10^{-3}[/tex] moles of [tex]Na_{2}CO_{3}[/tex]
There are [tex]9.30\times 10^{-3}\times 6.022\times 10^{23}\ \text{molecules of}\ Na_{2}CO_{3}=56\times 10^{20}\ \text{molecules}[/tex]
1 molecule of [tex]Na_{2}CO_{3}[/tex] contains 1 atom of carbon
i.e. there are [tex]56\times 10^{20}\ \text{atoms of C}[/tex]
