Answer:
Mass = 18.29 g
Explanation:
Given data:
Mass of beryllium needed = ?
Mass of nitrogen = 18.9 g
Solution:
Chemical equation:
3Be + N₂ → Be₃N₂
Number of moles of nitrogen:
Number of moles = mass/molar mass
Molar mass of nitrogen = 28 g/mol
Number of moles = 18.9 g/ 28 g/mol
Number of moles = 0.675 mol
Now we will compare the moles of nitrogen and Be.
N₂ : Be
1 : 3
0.675 : 3/1×0.675 = 2.03 mol
Mass of Be:
Mass = number of moles × molar mass
Mass = 2.03 mol × 9.01 g/mol
Mass = 18.29 g
