SUP= 125 UPE=110 SRE=85 find SUR

Answer:
m∠SUR = 15°
Step-by-step explanation:
m∠UPE = 110°
m∠UPR = m∠EPR [Given]
m∠UPR = [tex]\frac{1}{2}(m\angle UPE)[/tex]
= [tex]\frac{1}{2}(110)[/tex]
= 55°
Since, m∠SRU = m∠UPR [Given in the picture]
m∠SRU = 55°
m∠SRE = m∠SRU + m∠URP + m∠PRE
85° = 55° + m∠URP + m∠PRE
m∠URP + m∠PRE = 30°
Since, m∠URP = m∠PRE
m∠URP + m∠URP = 30°
m∠URP = 15°
Since, m∠URP = m∠SUR [Given in he picture]
m∠SUR = 15°