Answer:
The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²
Explanation:
The given parameters is as follows;
The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g
The required information = The number of formula units of potassium chloride (KCl)
The Molar Mass of KCl = 74.5513 g/mol
[tex]The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The \ mass \ of \ the substance}{The \ Molar \ Mass \ of \ the \ substance}[/tex]
Therefore, we have;
[tex]The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles[/tex]
1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units
Therefore;
0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units
From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.
The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²
Given:
Mass of KCl= 3.81 g
To find:
Formula units of KCl=?
Molar Mass of KCl = 74.55 g/mol
So, substituting the values in order to calculate number of moles
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} \\\\\text{Number of moles}=\frac{3.81}{74.55} \\\\\text{Number of moles}=0.051 \text{ moles}[/tex]
1 mole of a substance = Avogadro's number (6.022 × 10²³) of formula units
Thus, 0.051 moles of KCl will contain
[tex]0.051106 * 6.022 * 10^{23} =3.077588 * 10^{22} \text{ formula units}[/tex]
→The number of formula units in 3.81 g of potassium chloride (KCl)
= 3.08 × 10²² formula units.
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