Answer:
1a) 67.2 kg
1b) 66.5 kg
1c) 64 kg, 68 kg
2a) Mean = 58.1m, Median = 55m, Mode = 49m
2b) The mode is not a good measure since all data except 49m appeared twice i.e. the data set is quite distributed. (sorry I am not very sure with this answer)
3a) Independent variable is time, Dependent variable is distance.
3b) See attachment.
3c) Linear
3d) 2.5s: 10m 6.25s: 25m 8s: 32m
3e) 3m: 0.75s 21m: 5.25s. 36m: 9s.
Step-by-step explanation:
1a) Mean = (74+71+68+84+54+60+64+68+65+64)/10 kg = 67.2 kg
1b) Sort the data in ascending order (in kg).
54 60 64 64 65 68 68 71 74 84
Median = (65+68)/2 kg = 66.5 kg
1c) Mode = 64 kg, 68 kg (both appeared twice)
2a) Mean = (45+52+47+55+62+80+71+60+84+57+46+50+48+61+49+63+54+49+72)/19 m = 58.1m (correct to 1 decimal place)
Arrange the data in ascending order (in m).
45 46 47 48 49 49 50 52 54 55 57 60 61 62 63 71 72 80 84
Median = 55m
Mode = 49m (appeared twice)
2b) See answer.
3a) Independent variable is the variable that is to be changed. Dependent variable is the variable that is to be measured.
3b) Just plot the graph.
3c) Distance = 4 x time
3d) 2.5 x 4 = 10m. 6.25 x 4 = 25m. 8 x 4 = 32m.
3e) 3/4=0.75s. 21/4=5.25s. 36/4=9s.
