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A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force of 5N along the entire length. What is the velocity of the box when it reaches the end of the surface.

A. 25m/s

B. 2500m/s

C. 50m/s

D. 75m/s

Respuesta :

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Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

  • 5 N = 1 kg * a
  • a = 5 m/s²

List out known variables:

  • v₀ = 0 m/s
  • a = 5 m/s²
  • v = ?
  • Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

  • v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

  • v² = (0)² + 2(5)(250)
  • v² = 2500
  • v = 50 m/s

The final velocity of the box is C) 50 m/s.

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