I NEED HELP ASAP

Write an equation in point-slope form with the given characteristics Passes through (1,8) and (-2,3)​

Respuesta :

We first solve to find the slope. The slope of the line is 5/3. Then we substitute that into the formula that is y-y1=m(x-x1). M represents the slope of the line and the x and y’s represent the point values. So we get 8-3=5/3(1+2). We get this solution if it asks you to figure out the slope along the way too.

If they ask you the equation when knowing only the two points you do 8-3=m(1+3)

They both mean the same thing ( it just depends on what the problem is specifically asking you about)

Answer:

[tex]y - 8 = \frac{5}{3}(x - 1)[/tex]

Step-by-step explanation:

1) Use the slope formula, [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex], and the given points to find the slope. [tex]x_1[/tex] and [tex]y_1[/tex] represent the x and y values of one point the line must intersect, and [tex]x_2[/tex] and [tex]y_2[/tex] represent the x and y values of another point the line must also intersect:

[tex]\frac{(3)-(8)}{(-2)-(1)}[/tex]

= [tex]\frac{-5}{-3}[/tex]

= [tex]\frac{5}{3}[/tex]

2) Using the point-slope formula, [tex]y-y_1 = m (x - x_1)[/tex], use the slope you just calculated and substitute it for m. Choose any of the two points given (I chose (1,8)) and substitute its x and y values for [tex]x_1[/tex] and [tex]y_1[/tex]. Don't worry, the equation of the line is the same no matter which point you choose (unless the question specifies which one you need to choose):

[tex]y - 8 = \frac{5}{3}(x - 1)[/tex]