Answer:
An equation of the circle with centre (5,7) and radius 2 is [tex]\mathbf{(x-5)^2+(x-7)^2=4}[/tex]
Option A is correct.
Step-by-step explanation:
A circle in the xy-plane has centre (5,7) and radius 2. Which of the following is an equation of the circle.
The equation of circle is of form: [tex](x-h)^2+(x-k)^2=r^2[/tex] where (h,k) is centre and r is radius.
We have centre (5,7) so, we have h = 5 and k = 7
We have radius = 2 so, r = 2
Putting values in the equation and finding the required equation:
[tex](x-h)^2+(x-k)^2=r^2\\(x-5)^2+(x-7)^2=(2)^2\\(x-5)^2+(x-7)^2=4[/tex]
So, an equation of the circle with centre (5,7) and radius 2 is [tex]\mathbf{(x-5)^2+(x-7)^2=4}[/tex]
Option A is correct.
