I WILL GIVE BRAINLIEST IF YOU GET IT RIGHT!!!!

The figure below shows a square ABCD and an equilateral triangle DPC:


ABCD is a square. P is a point inside the square. Straight lines join points A and P, B and P, D and P, and C and P. Triangle D


Jake makes the chart shown below to prove that triangle APD is congruent to triangle BPC:


Statements Justifications

In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal

Sides of square ABCD are equal

In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° − 60° = 30°

Triangles APD and BPC are congruent SAS postulate

Which of the following completes Jake's proof? (1 point)


In triangles APD and BPC; AD = BC

In triangles APD and BPC; AP = PB

In triangles APB and DPC; AD = BC

In triangles APB and DPC; AP = PB.