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11. The price of a bottle of water at a store decreases from $1.65 to $1.40. Rounded to the nearest
tenth of a percent, what is the percent decrease in the price of the bottle of water?
A. 15.2%
B. 17.9%
C. 45.9%
D. 54.1%

Respuesta :

bookgirl9632

Answer:

A. 15.2%

Step-by-step explanation:

Subtract the new price from the old one to find the dollar amount that the water bottle price was reduced.

[tex]1.65-1.40=0.25[/tex]

The price was reduced by 25 cents, but we need to find the percentage. To do that, we divide the price reduction by the original price.

[tex]0.25/1.65=0.152[/tex]

And then move the decimal place over two spots (multiply by 100)

15.2

Percent decrease in the price of the bottle of water is 15.2% (Approx.)

Given that;

Older price of bottle = $1.65

New price of bottle = $1.40

Find:

Percent decrease in the price of the bottle of water

Computation:

Percent decrease in the price of the bottle of water = [(1.65 - 1.40) / 1.65]100

Percent decrease in the price of the bottle of water = [(0.25) / 1.65]100

Percent decrease in the price of the bottle of water = [(0.25) / 1.65]100

Percent decrease in the price of the bottle of water = 15.2% (Approx.)

Learn more:

https://brainly.com/question/10156335?referrer=searchResults

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