Respuesta :
Answer:
[tex]\frac{7}{24}[/tex]
Step-by-step explanation:
The cotangent of [tex]m\angle B[/tex] can be represented as [tex]\frac{1}{\tan (m\angle B)}[/tex]. Using trig rules for a right triangle, we can write the following equation:
[tex]\tan B=\frac{24}{7}[/tex].
Therefore, the cotangent of [tex]m\angle B[/tex] is:
[tex]\cot B = \frac{1}{\tan B}=\frac{1}{\frac{24}{7}}=\fbox{$\frac{7}{24}$}[/tex].
The ratio of cotangent of angle B is [tex]\frac{7}{24}[/tex]. for understanding check the calcualtiion here ,
From the given information ,
In ΔABC, the measure of ∠C=90°, CB = 7, BA = 25, and AC = 24
Contangent of any angle is equal to adjacent side divide by opposite side
Cotangent of an angle is a relationship found by dividing the length of the side adjacent to given angle by the length of side opposite to the given angle.
The side opposite to angle B is CB and side opposite of angle B is AC
cot (B) = adjacent side / opposite side
[tex]cot(B)=\frac{CB}{AC}[/tex]
CB = 7, BA = 25, and AC = 24
[tex]cot (B)=\frac{7}{24}[/tex]
The ratio of cotangent of angle B is [tex]\frac{7}{24}[/tex]
Learn more information about 'cotangent ' here
brainly.com/question/10430279
