Answer:
Step-by-step explanation:
cot θ=11
tan θ=1/11
[tex]\sin ~2\theta=\frac{2 \tan ~\theta}{1+\tan^2 \theta} =\frac{2*\frac{1}{11} }{1+(\frac{1}{11} )^2}=\frac{22 }{122} \\\\cos~2 \theta=\frac{1-tan^2 \theta}{1+tan^2\theta} =\frac{1-(\frac{1}{11})^2 }{1+(\frac{1}{11} )^2} =\frac{120}{122} =\frac{60}{61} \\tan 2 \theta=\frac{2 tan\theta}{1-tan^2 \theta} =\frac{2*(\frac{1}{11 } )}{1-(\frac{1}{11} )^2} =\frac{2*11}{120} =\frac{11}{60}[/tex]
