Answer:
[tex]g\left(1\right)=-\frac{1}{5}[/tex]
Step-by-step explanation:
Given
Let the function
[tex]g\left(x\right)=\frac{x^2-3}{10}[/tex]
To determine
g(1) = ?
Given the function
[tex]g\left(x\right)=\frac{x^2-3}{10}[/tex]
substitute x = 1
[tex]g\left(1\right)=\frac{\left(1\right)^2-3}{10}[/tex]
[tex]=\frac{\left(1\right)^2-3}{10}[/tex]
[tex]=\frac{1-3}{10}[/tex]
[tex]=\frac{-2}{10}[/tex]
[tex]=-\frac{2}{10}[/tex]
[tex]=-\frac{1}{5}[/tex]
Therefore,
[tex]g\left(1\right)=-\frac{1}{5}[/tex]
