Answer:
Percentage of O = 56.1 %
Percentage of Al =15.8%
Percentage of S = 28.1 %
Explanation:
Given compound Al₂(SO₄)₃
Molar mass of compound:
27×2 + 32×3 + 16×12 = 342 g/mol
Percentage of Al = ( Mass of Al / Total mass ) × 100
Percentage of Al = 54 /342 × 100
Percentage of Al =15.8%
Percentage of S = ( Mass of S / Total mass ) × 100
Percentage of S = 96 /342 × 100
Percentage of S = 28.1 %
Percentage of O = ( Mass of O / Total mass ) × 100
Percentage of O = 192 /342 × 100
Percentage of O = 56.1 %
