The time needed for passengers to board the Twisting Thunder roller coaster is skewed right with a mean of 49
seconds and a standard deviation of 7.1 seconds. The time to board the Spiral Wonder roller coaster is skewed left
with a mean of 44.8 seconds and a standard deviation of 3.7 seconds. What is the probability in a random sample of
32 times loading Twisting Thunder and 36 times loading Spiral Wonder that the mean time for Twisting Thunder is
less than that of Spiral Wonder?

Respuesta :

Answer:

0.1416

Step-by-step explanation:

The probability in a random sample of 32 times loading Twisting Thunder and 36 times loading Spiral Wonder is 0.9574.

What is normal a distribution?

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The time needed for passengers to board the Twisting Thunder roller coaster is skewed right with a mean of 49 seconds and a standard deviation of 7.1 seconds.

The probability in a random sample of 32 will be

[tex]z = \dfrac{x - \mu}{\sigma}\\\\z = \dfrac{32 - 49}{7.1}\\\\z = -2.394[/tex]

P-value from Z-Table:

P(x<32) =

The time to board the Spiral Wonder roller coaster is skewed left with a mean of 44.8 seconds and a standard deviation of 3.7 seconds.

The probability in a random sample of 36 will be

[tex]z = \dfrac{x - \mu}{\sigma}\\\\z = \dfrac{36- 44.8}{3.7}\\\\z = -2.37838[/tex]

P-value from Z-Table:

P(x<36) = 0.0086945

The probability in a random sample of 32 times loading Twisting Thunder and 36 times loading Spiral Wonder will be

[tex]\rm \dfrac{P(x < 32)}{P(x < 36)} = \dfrac{0.0083246}{0.0086945} = 0.9574[/tex]

More about the normal distribution link is given below.

https://brainly.com/question/12421652