Answer:
B) [tex]\frac{2}{3}[/tex]
Explanation:
The electric force between charges can be determined by;
F = [tex]\frac{kq_{1} q_{2} }{r^{2} }[/tex]
Where: F is the force, k is the Coulomb's constant, [tex]q_{1}[/tex] is the value of the first charge, [tex]q_{2}[/tex] is the value of the second charge, r is the distance between the centers of the charges.
Let the original charge be represented by q, so that;
[tex]q_{1}[/tex] = 2q
[tex]q_{2}[/tex] = [tex]\frac{q}{3}[/tex]
So that,
F = [tex]q_{1}[/tex][tex]q_{2}[/tex] x [tex]\frac{k}{r^{2} }[/tex]
= 2q x [tex]\frac{q}{3}[/tex] x [tex]\frac{k}{r^{2} }[/tex]
= [tex]\frac{2q^{2} }{3}[/tex] x [tex]\frac{k}{r^{2} }[/tex]
= [tex]\frac{2}{3}[/tex] x [tex]\frac{kq}{r^{2} }[/tex]
F = [tex]\frac{2}{3}[/tex] x [tex]\frac{kq}{r^{2} }[/tex]
The electric force between the given charges would change by [tex]\frac{2}{3}[/tex].
