Respuesta :

Answer:-

[tex]x {}^{2} + 8x + 15 = 0[/tex]

[tex]x^2 -5x-3 x +15=0[/tex]

[tex]x(x-5)-3(x-5)=0[/tex]

[tex](x-5)(x-3)=0[/tex]

[tex]x=5,3[/tex]

Hope its Helpful!

Answer: x = -3, -5

Step-by-step explanation:

Solve by Factoring

x^2 + 8x + 15 = 0

Factor x2 + 8x + 15 using the AC method.

  Consider the form x2 + bx + c. Find a pair of i ntegers whose product is c and whose sum is b. In this case, whose product is 15 and whose sum is 8.

3, 5

  Write the factored form using these integers.

     (x + 3) (x + 5) = 0  

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

x + 3 = 0

x + 5 = 0

Set x + 3 equal to 0 and solve for x.

  Set x + 3 equal to 0.

     x + 3 = 0

  Subtract 3 from both sides of the equation.

     x = −3

Set x + 5 equal to 0 and solve for x.

  Set x + 5 equal to 0.

     x + 5 = 0

   Subtract 5 from both sides of the equation.

     x = −5

 The final solution is all the values that make (x + 3) (x + 5) = 0 true.

     x = −3, −5