Given:
Total number of beans = 20
Number of blue of beans = 8
One bean is selected from the bag at random.
To find:
The probability that she will draw a bean that is NOT blue.
Solution:
We have,
Total number of beans = 20
Number of blue of beans = 8
Number of non-blue beans = 20 - 8
= 12
Now, the probability that she will draw a bean that is NOT blue is
[tex]P(\text{Bean is not blue})=\dfrac{\text{Number of non-blue beans}}{\text{Total number of beans}}[/tex]
[tex]P(\text{Bean is not blue})=\dfrac{12}{20}[/tex]
[tex]P(\text{Bean is not blue})=\dfrac{3}{5}[/tex]
Therefore, the correct option is C.
