Answer:
[tex]\mathrm{C)\:}x=15,\:-7[/tex]
Step-by-step explanation:
For [tex]|a-b|=c[/tex], there are two possible cases:
[tex]\begin{cases}a-b=c\\a-b=-c\\\end{cases}[/tex]
Solving for both cases, we get:
[tex]\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}[/tex]
