Respuesta :
Answer:
[tex]a.\: \frac{1}{12}[/tex]
Step-by-step explanation:
The probability he will roll an odd number on the first roll is [tex]\frac{1}{2}[/tex] as there are three odd numbers and three even numbers on a fair six-sided dice.
The probability he will roll the number 4 on the second roll is [tex]\frac{1}{6}[/tex] as out of the six numbers, only one is the number 4.
Therefore the probability of both happening is [tex]\frac{1}{2}\cdot \frac{1}{6}=\fbox{$a.\: \frac{1}{12}$}[/tex].