Answer:
See detailed explanation.
Explanation:
Hello!
In this case, for the described chemical reaction, we can proceed as follows:
A) For the complete chemical reaction we note down every reacted and produced species as well as the proper balancing process:
[tex]2NaBr(aq)+Cl_2(aq)\rightarrow 2NaCl(aq)+Br_2(g)[/tex]
In which gaseous bromine may give off.
B) The dissociated ionic equation requires the ionization of the aqueous species in ions, expect for chlorine which is not ionized:
[tex]2Na^+(aq)+2Br^-(aq)+Cl_2(aq)\rightarrow 2Na^+(aq)+2Cl^-(aq)+Br_2(g)[/tex]
C) For the net ionic equation we cancel out the sodium ions as they are at both reactants and products:
[tex]2Br^-(aq)+Cl_2(aq)\rightarrow +2Cl^-(aq)+Br_2(g)[/tex]
D) Based on C) we infer that the spectator ions here are the sodium ions.
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