If the distance from the center of a Ferris wheel to one of the seats is approximately 90 feet what is the distance traveled by a seated person, to the nearest foot, in four revolutions r=90 feet

Step-by-step explanation: One trip around is one circumference of a circle. The circumference is 2πr. That's 2(π)(90 ft) = 565.4867 ft. Multiply by 4 trips around for a total distance of 2261.9 ft If you care about significant figures, then you only have report sig fig, so that's 2000 ft.

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alokdubeyvidyaatech alokdubeyvidyaatech · Answer 2 · 2022-01-22T12:45:26+01:00

The total distance traveled by the seated person is 2260.8 feet.

How do you calculate the distance?

Given that the distance from the center of the wheel to the seat is 90 feet. The seated person travels for 4 revolutions.

The distance traveled by the seated person in one revolution will be equal to the circumference of the wheel has a radius of r. Hence the circumference of the wheel is given below.

One revolution = [tex]2\pi r[/tex]

One revolution = [tex]2 \times 3.14\times 90[/tex]

One revolution = 565.2 feet

Hence the distance covered in four revolutions can be calculated as below.

Total Distance = [tex]4 \times 565.2[/tex]

Total Distance = 2260.8 feet

Hence we can conclude that the total distance traveled by the seated person is 2260.8 feet.

To know more about the distance, follow the link given below.

https://brainly.com/question/1214027.