basket contains 7 green apples, 9 red apples, 10 nectarines, and 10 oranges. Sandy randomly chooses a piece of fruit, eats it, then selects another. Find the probability of selecting a red apple then a oranges?

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carolmartelotte2020 carolmartelotte2020 · Answer 1 · 2021-01-14T19:37:59+01:00

Answer:

So the probability is 1/14 or 7.14%

Step-by-step explanation:

First lets calculate the total number of fruits:

[tex]7+9+10+10=36[/tex]

Now, calculating the probability of the first fruit being a red apple, we have 9 red apples among 36 fruits, so the probability is 9/36.

Then the probability of the second fruit being an orange will be 10/35 , since we will have 10 oranges among 35 fruits.

Finally the final probability is the product of these two probabilities , so we have:

[tex]P=\frac{9}{36} .\frac{10}{35} =\frac{1}{4} .\frac{2}{7} =\frac{1}{14}[/tex]

So the probability is 1/14 or 7.14%

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