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Use a combination to answer the following question.

The track coach needs to higher three managers for the track team. If ten students applied for the positions,

How many ways can the coach select three managers from 10 students?

n=
r=

Answer:

(answer with no comas or decimals)

Respuesta :

Answer:

   120 possible combinations

Step-by-step explanation:

We have to find the combination of 10 students in 3 positions, where the order does not matter.

[tex]n=10\\r=3\\[/tex]

Then, the combination can be calculated as :

[tex]C(n.r)= \frac{n!}{(n-r)!r!} \\C(10,3)=\frac{10!}{10-3)!3!} =\frac{10!}{7!.3!} = \frac{10.9.8}{3.2} =\frac{720}{6} =120[/tex]

Answer : 120 possible combinations

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