The speed of the block after the student pushes it is 10m/s.
Given the data in the question;
- Mass of block; [tex]m = 12kg[/tex]
Since the block is initially at rest,
- Initial velocity; [tex]u = 0[/tex]
- Time taken; [tex]t = 5s[/tex]
- Acceleration; [tex]a = 2m/s^2[/tex]
Final velocity; [tex]v =\ ?[/tex]
To determine the final velocity; we use the First Equation of Motion:[tex]v = u + at[/tex]
Where v is final velocity, u is initial velocity, a is acceleration and t is time taken.
We substitute our values into the equation
[tex]v = 0 + [ 2m/s^2\ *\ 5s]\\\\v = 2m/s^2\ *\ 5s\\\\v = 10\frac{ms}{s^2}\\\\v = 10m/s[/tex]
Therefore, the speed of the block after the student pushes it is 10m/s.
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