Answer:
(- [tex]\frac{8}{5}[/tex], [tex]\frac{46}{5}[/tex] )
Step-by-step explanation:
Given the2 equations
6 - 2x = y → (1)
14 + 3x = y → (2)
Substitute y = 14 + 3x into (1)
6 - 2x = 14 + 3x ( subtract 3x from both sides )
6 - 5x = 14 ( subtract 6 from both sides )
- 5x = 8 ( divide both sides by - 5 )
x = - [tex]\frac{8}{5}[/tex]
Substitute x = - [tex]\frac{8}{5}[/tex] into either of the 2 equations for the corresponding value of y
Substituting into (1)
y = 6 - 2(- [tex]\frac{8}{5}[/tex] ) = [tex]\frac{30}{5}[/tex] + [tex]\frac{16}{5}[/tex] = [tex]\frac{46}{5}[/tex]
solution is ( - [tex]\frac{8}{5}[/tex], [tex]\frac{46}{5}[/tex] )