A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing in a northwesterly direction (45 degrees west of North). Considering the initial velocity of the ball and the velocity of wind, what will be the resultant velocity (m/s) and the resultant direction of the golf ball assuming no other forces are acting on the ball

Respuesta :

Answer:

[tex]c=71.4m/s[/tex]

[tex]\theta=8.54\textdegree[/tex]

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed [tex]V_w= 15 m/s \angle 45 \textdegree[/tex]

Generally Resolving vector mathematically

  [tex]sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6[/tex]

Generally the equation Pythagoras theorem is given mathematically by

[tex]c^2=a^2+b^2[/tex]

[tex]c^2=10.6^2 +(10.6+60)^2[/tex]

[tex]c=\sqrt{10.6^2 +(10.6+60)^2}[/tex]

Therefore Resultant velocity (m/s)

[tex]c=71.4m/s[/tex]

b)Resultant direction

Generally the equation for solving Resultant direction

[tex]\theta=tan^-1(\frac{y}{x})[/tex]

Therefore

[tex]\theta=tan^-1(\frac{10.6}{70.6})[/tex]

[tex]\theta=8.54\textdegree[/tex]