Answer:
[tex]F_f=840N[/tex]
Explanation:
From the question we are told that
Weight of fireman [tex]W_f= 87.5kg[/tex]
Pole distance [tex]D=4.10m[/tex]
Final speed is [tex]V_f 1.75m/s[/tex]
Generally the equation for velocity is mathematically represented as
[tex]v^2 = v_0^2 + 2 a d[/tex]
Therefore Acceleration a
[tex]a'= v^2 / 2 d[/tex]
[tex]a'= 0.21m/s^2[/tex]
Generally the equation for Frictional force [tex]F_f[/tex] is mathematically given as
[tex]F_f=m*a[/tex]
[tex]F_f=m*(g-0.21)[/tex]
[tex]F_f=87.5*(9.81-0.21)[/tex]
Therefore
[tex]F_f=840N[/tex]
