Answer:
The molar concentration of normal saline is 0.15 mol/L.
Explanation:
The mass of NaCl in 0.85% of normal saline is:
[tex] 0.85 \% = \frac{0.85 g}{100 ml} [/tex]
[tex] m_{NaCl} = 0.85 g [/tex]
The molar concentration can be found using the following equation:
[tex] C = \frac{n}{V} [/tex]
So we need to find the number of moles of NaCl in 1 liter of solution.
[tex]m_{NaCl} = \frac{0.85 g}{100 mL}*\frac{1000 mL}{1 L}*1 L = 8.5 g[/tex]
[tex]n = \frac{m_{NaCl}}{M}[/tex]
Where:
M: is the molar mass of NaCl = 58.44 g/mol
[tex] n = \frac{8.5 g}{58.44 g/mol} = 0.15 moles [/tex]
Hence, the molar concentration is:
[tex]C = \frac{0.15 moles}{1 L} = 0.15 mol/L[/tex]
Therefore, the molar concentration of normal saline is 0.15 mole per liter.
I hope it helps you!
