Answer:
[tex]|A| = - 28[/tex]
Step-by-step explanation:
Given
[tex]A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right][/tex]
Required
Determine the determinant
For a two by two matrix, A such that:
[tex]A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right][/tex]
The determinant |A| is:
[tex]|A| = a * d - b * c[/tex]
So, in
[tex]A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right][/tex]
The determinant is:
[tex]|A| = -2 * 5 - 6 * 3[/tex]
[tex]|A| = -10 - 18[/tex]
[tex]|A| = - 28[/tex]
