Step-by-step explanation:
Hey there!
Given equation is; 6x + y= 6.
6x + y -6=0........……(i)
Slope (m1) = (-coefficient of X)/(coefficient. of y)
Slope (m1) = (-6)/(1)
Therefore, slope of the equation is -6.
As per the condition of parallel lines, slope of 1st equation is equal to 2nd equation.
Therefore, m1=m2= -6
The another straight line passes through the point (2,-5). So to find the equation, use one-point formula.
(i.e (y-y1) = m2(x-x1)).
So, the equation is;
(y+5) = m2(x-2)
Now, we know that m1=m2= -6. Let's keep its value on it.
y+5 = -6(x-2)
Or, y+5 = -6x +12
Or, 6x+ y -7 = 0
Therefore, the equation which is parallel to 6x + y= 6 equation and passes through the point (2,-5) is 6x+y-7=0.
Hope it helps...
