Respuesta :

Space

Answer:

7.53 × 10²³ molecules NaOH

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

50.0 g NaOH

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol

Step 3: Convert

  1. Set up:                              [tex]\displaystyle 50.0 \ g \ NaOH(\frac{1 \ mol NaOH}{40 \ g \ NaOH})(\frac{6.022 \cdot 10^{23} \ molecules \ NaOH}{1 \ mol \ NaOH})[/tex]
  2. Multiply:                                                                                                           [tex]\displaystyle 7.5275 \cdot 10^{23} \ molecules \ NaOH[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

7.5275 × 10²³ molecules NaOH ≈ 7.53 × 10²³ molecules NaOH

Otras preguntas