14 part a and b. While at the park, you decide to purchase a hamburger for $3.26 and 3 bottles of water. If you purchase the hamburger and 3 bottles of water, pay with a $9.50 bill, and receive no change, then how much did each bottle of water cost? You are required to answer the following parts. Part A - Write and solve the equation

Respuesta :

Answer:

[tex]3.26 + 3B = 9.50[/tex]

A bottle water costs $2.08

Explanation:

Given

Represent the hamburger with H

Represent the bottles of water with B

[tex]Total = \$9.50[/tex]

Solving (a): Represent as an equation

1 hamburger = 3.26

3 bottles of water = 3 * B

Total = 9.50

The system is represented as thus:

1 hamburger + 3 bottles of water =  Total

Substitute values

[tex]3.26 + 3 * B = 9.50[/tex]

[tex]3.26 + 3B = 9.50[/tex]

Solving (b): The cost of bottle water

[tex]3.26 + 3B = 9.50[/tex]

Make 3B the subject

[tex]3B = 9.50 - 3.26[/tex]

[tex]3B = 6.24[/tex]

Divide both sides by 3

[tex]\frac{3B}{3} = \frac{6.24}{3}[/tex]

[tex]B = \frac{6.24}{3}[/tex]

[tex]B = 2.08[/tex]

A bottle water costs $2.08