The program manager for an amateur performance night auditioned 12 acts, but there is only room for 3 acts on the program. How many different ways can the program manager arrange 3 different acts from the original 12

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Answer:

There are 220 different ways to arrange the acts.

Step-by-step explanation:

The order in which the acts are arranged is not important, so we use the combinations formula to solve this question.

Combinations Formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

How many different ways can the program manager arrange 3 different acts from the original 12

Three acts from a set of 12. So

[tex]C_{12,3} = \frac{12!}{3!(12-9)!} = 220[/tex]

There are 220 different ways to arrange the acts.