a. Gas A has the lowest rate of diffusion
Given
The molar masses
Required
the lowest rate of diffusion
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
So :
[tex]\tt r\approx \dfrac{1}{\sqrt{M} }[/tex]
The greater the molar mass, the smaller the rate
So gas A has the lowest rate