find angle A and angle B..
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Step-by-step explanation:
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
[tex]\tt{\angle{c}=110°}[/tex]
and,
[tex]\tt{BC=AC} [/tex]
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[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
☆Find the [tex]\angle{B} ~and~\angle{A} [/tex]
[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
Here,
BC =AC
so,
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[tex]\angle{A}=\angle{B} [/tex]
we know that,
[tex]\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}} [/tex]
But [tex]\angle{C}=110° [/tex](Ģìvéñ)
so..
[tex]\angle{A}+\angle{B}+110°=180° [/tex]
[tex]\angle{A}+\angle{A}+110°=180° [/tex]
[tex]\because{\angle{A}=\angle{B} } [/tex]
[tex]2\angle{A}=180°-110° [/tex]
[tex]2\angle{A}=70° [/tex]
[tex]\angle{A}=\dfrac{70°}{2} [/tex]
[tex]\boxed{\orange{\angle{A}=35°}} [/tex]
But...
[tex]\angle{A}=\angle{B} [/tex]
soo,
[tex]\boxed{\orange{\angle{B}=35°}} [/tex]
[tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
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[tex]\boxed{\green{\angle{A}=35°}} [/tex]
[tex]\boxed{\green{\angle{B}=35°}} [/tex]