Answer:
[tex]F$\approx$76[/tex]
Explanation:
From the question we are told that
Point charges [tex]q_1=1.60uC[/tex]
[tex]q_2=-22.25uC[/tex]
Displacement [tex]d=6.50cm=>0.065m[/tex]
Generally the equation for Coulomb's law is Mathematically given as
[tex]F=\frac{k*q_1*q_2}{r^2}[/tex]
Therefore
[tex]F=\frac{9*10^9*-22.25*10^-^6*(1.60)*10^-^6}{(6.50*10^-^2)^2}[/tex]
[tex]F=-75.83431953[/tex]
[tex]F$\approx$-76[/tex]
with -(negative) showing form of force Magnitude => [tex]F$\approx$76[/tex]
