Answer:
[tex]V=202mL[/tex]
Explanation:
Hello!
In this case, considering we have a 5.11-molar solution (5.11 M) that contains 175. g of silver nitrate, we first need to compute the moles of solute as its molar mass is 169.87 g/mol:
[tex]n=175g*\frac{1mol}{169.87 g} =1.03mol[/tex]
Next, since the definition of molarity is moles over volume:
[tex]M=\frac{n}{V}[/tex]
We solve for the volume and plug in the molarity and moles as shown below:
[tex]V=\frac{n}{M} =\frac{1.03mol}{5.11mol/L}\\\\V =0.202L[/tex]
However, as it is needed in milliliters, we convert the L to mL:
[tex]V=0.202L*\frac{1000mL}{1L}\\\\V=202mL[/tex]
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