The given question is incomplete. The complete question is:
A chemist adds 245.0 ml 0.0238 M of a aluminum chloride solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to two significant digits.
Answer: The millimoles of aluminum chloride are 5.8
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = milli moles of solute
[tex]V_s[/tex] = volume of solution in ml
Now put all the given values in the formula of molarity, we get
[tex]0.0238=\frac{n}{245.0}[/tex]
[tex]n=5.8[/tex]
Therefore, the millimoles of aluminum chloride are 5.8
