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Given that ABCD is a rhombus, what is the value of x?
в
с
(3x + 12)"
A
O A. 19.5
B. 78
O C. 15.8
O D. 26
E. 52
ОО
F. Cannot be determined

Given that ABCD is a rhombus what is the value of x в с 3x 12 A O A 195 B 78 O C 158 O D 26 E 52 ОО F Cannot be determined class=

Respuesta :

akposevictor

Answer:

A. 19.5

Step-by-step explanation:

Diagonals of a rhombus intersect at right angles. Therefore the angle opposite to AD = 90°.

Thus:

90° + x + 3x + 12 = 180° (sum of ∆)

Add like terms

102 + 4x = 180

Subtract 102 from each side

4x = 180 - 102

4x = 78

Subdue both sides by 4

x = 19.5

balabedali939816

Answer:

Step-by-step explanation:

It’s A

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