Given that,
Temperature, T = 1500 K
Wavelength, [tex]\lambda=4.5\times 10^2\ nm[/tex]
To find,
The energy of one photon of this light.
Solution,
We know that, the energy of a photon is given by the formula as follows :
[tex]E=\dfrac{hc}{\lambda}\\\\E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{4.5\times 10^2\times 10^{-9}}\\\\=4.42\times 10^{-19}\ J[/tex]
So, the required energy is [tex]4.42\times 10^{-19}\ J[/tex].
