Answer:
Worker B needs 9 days to finish the rest of the work
Step-by-step explanation:
Proportions
Worker A finishes a project on his own in 12 days and worker B does the same in 16 days.
Worker A does 1/12 of the project in one day and worker B does 1/16 of the project in one day. When working together, they do
[tex]\frac{1}{12}+\frac{1}{16}=\frac{7}{48}[/tex]
After 3 days they have completed:
[tex]3*\frac{7}{48}=\frac{7}{16}[/tex]
parts of the project, this means it still remains:
[tex]1-\frac{7}{16}=\frac{9}{16}[/tex]
parts of the project and it is done by B alone. Since B does [tex]\frac{1}{16}[/tex] per day, he now takes
[tex]\displaystyle \frac{\frac{9}{16}}{\frac{1}{16}}=9[/tex]
days to complete the project.
Worker B needs 9 days to finish the rest of the work
